Question

\(\frac{2x+1}{3}=\frac{5}{2}\)

\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)

\(\left(\frac{3x}{7}+1\right):-4=\frac{-1}{28}\) 

trả lời giúp mình, ngày mai mình thi rồi giúp mình với, mình sẽ tích

Answer 1

\(\frac{2x+1}{3}=\frac{5}{2}\)

\(2x+1=\frac{5.3}{2}=\frac{15}{2}\)

2x=  15/2 - 1 = 13/2

x = 13/2 : 2

x = 13/4 

b) 2^x + 2^x+1 + 2^x+2 + 2^x+3 = 480

2^x.(1+ 2 +2² + 2³) = 480

2^x . 15 = 480

2^x = 480 : 15 = 32

2^x = 2⁵ => x = 5

c) \(\left(\frac{3x}{7}+1\right):\left(-4\right)=-\frac{1}{28}\)

\(\frac{3x}{7}+1=\frac{-1}{28}.\left(-4\right)=\frac{1}{7}\)

\(\frac{3x}{7}=\frac{1}{7}-1=-\frac{6}{7}\)

< = > 3x=  -6 => x = -2

 

Answer 2

Answer 3

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Answer 4

a,\(\frac{2x+1}{3}=\frac{5}{2}\) <=> (2x+1).2=3.5 <=> 4x +2 =15 <=> 4x = 15-2 <=> 4x = 13 <=> x= 13/4

Answer 5

c, (3x/7 +1) : -4 = -1/28

<=> 3x/7 +1 = \(\frac{-1}{28}\).(-4)

<=> 3x/7+1=1/7

<=> 3x/7= 1/7-1

<=> 3x/7 = -6/7

<=> 3x= -6

<=> x=-2