a) \(-\frac{3}{2}.\left(7-\frac{1}{6}\right)+4.\left(x-\frac{1}{2}\right)=3\)
\(\Rightarrow-\frac{3}{2}.\frac{41}{6}+4.\left(x-\frac{1}{2}\right)=3\)
\(\Rightarrow-\frac{41}{4}+4.\left(x-\frac{1}{2}\right)=3\)
\(\Rightarrow4.\left(x-\frac{1}{2}\right)=3-\left(-\frac{41}{4}\right)\)
\(\Rightarrow4.\left(x-\frac{1}{2}\right)=\frac{53}{4}\)
\(\Rightarrow x-\frac{1}{2}=\frac{53}{4}:4\)
\(\Rightarrow x-\frac{1}{2}=\frac{53}{16}\)
\(\Rightarrow x=\frac{53}{16}+\frac{1}{2}\)
\(\Rightarrow x=\frac{61}{16}\)
Vậy \(x=\frac{61}{16}\)
b) \(3.\left(x-\frac{1}{5}\right)-7.\left(\frac{5}{14}-3\right)=20\)
\(\Rightarrow3.\left(x-\frac{1}{5}\right)-7.\left(-\frac{37}{14}\right)=20\)
\(\Rightarrow3.\left(x-\frac{1}{5}\right)-\left(-\frac{37}{2}\right)=20\)
\(\Rightarrow3.\left(x-\frac{1}{5}\right)=20+\left(-\frac{37}{2}\right)\)
\(\Rightarrow3.\left(x-\frac{1}{5}\right)=\frac{3}{2}\)
\(\Rightarrow x-\frac{1}{5}=\frac{3}{2}:3\)
\(\Rightarrow x-\frac{1}{5}=\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{2}+\frac{1}{5}\)
\(\Rightarrow x=\frac{7}{10}\)
Vậy \(x=\frac{7}{10}\)
\(\Rightarrow x=\frac{53}{16}+\frac{1}{2}\)
