Question

(\(\frac{2}{5}\)-x)x(2x-\(\frac{1}{2}\))=0

Answer 1

\(\left(\frac{2}{5}-x\right).\left(2x-\frac{1}{2}\right)=0\)

=> \(\left\{{}\begin{matrix}\frac{2}{5}-x=0\\2x-\frac{1}{2}=0\end{matrix}\right.\) => \(\left\{{}\begin{matrix}x=\frac{2}{5}-0\\2x=0+\frac{1}{2}=\frac{1}{2}\end{matrix}\right.\) => \(\left\{{}\begin{matrix}x=\frac{2}{5}\\x=\frac{1}{2}:2\end{matrix}\right.\)

=> \(\left\{{}\begin{matrix}x=\frac{2}{5}\\x=\frac{1}{4}\end{matrix}\right.\)

Vậy \(x\in\left\{\frac{2}{5};\frac{1}{4}\right\}\).

Chúc bạn học tốt!