Question

\(\frac{2}{4-x}=\frac{-7}{x+1}\)

Answer 1

\(\frac{2}{4-x}=\frac{-7}{x+1}\)

\(\Rightarrow2\left(x+1\right)=\left(-7\right)\left(4-x\right)\)

\(\Rightarrow2x+2=\left(-28\right)+7x\)

\(\Rightarrow2x-7x=\left(-28\right)-2\)

\(\Rightarrow\left(-5\right)x=\left(-30\right)\)

\(\Rightarrow x=6\)

Vậy \(x=6\)

Answer 2

=>2*(x+1)=-7*(4-x)

=>2x+2=-28+7x

=>5X=30=>x=6