Violympic toán 9
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Giải hệ: \(\left\{{}\begin{matrix}\sqrt{x}+\sqrt{y}+\sqrt{z}-\frac{1}{\sqrt{x}}-\frac{1}{\sqrt{y}}-\frac{1}{\sqrt{z}}=\frac{8}{3}\\x+y+z+\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=\frac{118}{9}\\x\sqrt{x}+y\sqrt{y}+z\sqrt{z}-\frac{1}{x\sqrt{x}}-\frac{1}{y\sqrt{y}}-\frac{1}{z\sqrt{z}}=\frac{728}{27}\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\frac{2}{x}+\frac{1}{y+2}=2\\\frac{8}{x}-\frac{3}{y+2}=1\end{matrix}\right.\)
23 tháng 11 2019 lúc 12:51
1. gpt : \(\frac{2x+1}{\sqrt{x^2+2}}+\left(x+1\right)\sqrt{1+\frac{2x+1}{x^2+2}}+x=0\)
2. \(\left\{{}\begin{matrix}x,y,z>0\\x+y+z\le\frac{3}{2}\end{matrix}\right.\) Tìm min \(Q=\frac{x}{y^2z}+\frac{y}{z^2x}+\frac{z}{x^2y}+\frac{x^5}{y}+\frac{y^5}{z}+\frac{z^5}{x}\)
Nếu \(\left(x_0;y_0\right)\)là nghiệm của phương trình \(\left\{{}\begin{matrix}\frac{7}{x-y+2}-\frac{5}{x+y-1}=\frac{9}{2}\\\frac{6}{x-y+2}+\frac{4}{x+y-1}=8\end{matrix}\right.\)vậy \(\frac{y_0}{x_0}=...\)
giải hệ phương trình:
1, left{{}begin{matrix}2yleft(4y^2+3x^2right)x^4left(x^2+3right)2012^xleft(sqrt{2y-2x+5}-x+1right)4024end{matrix}right.
2, left{{}begin{matrix}x^3-2x^2y-15x6yleft(2x-5-4yright)frac{x^2}{8y}+frac{2x}{3}sqrt{frac{x^3}{3y}+frac{x^2}{4}}-frac{y}{2}end{matrix}right.
3, left{{}begin{matrix}8left(x^2+y^2right)+4xy+frac{5}{left(x+yright)^2}132x+frac{1}{x+y}1end{matrix}right.
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giải hệ phương trình:
1, \(\left\{{}\begin{matrix}2y\left(4y^2+3x^2\right)=x^4\left(x^2+3\right)\\2012^x\left(\sqrt{2y-2x+5}-x+1\right)=4024\end{matrix}\right.\)
2, \(\left\{{}\begin{matrix}x^3-2x^2y-15x=6y\left(2x-5-4y\right)\\\frac{x^2}{8y}+\frac{2x}{3}=\sqrt{\frac{x^3}{3y}+\frac{x^2}{4}}-\frac{y}{2}\end{matrix}\right.\)
3, \(\left\{{}\begin{matrix}8\left(x^2+y^2\right)+4xy+\frac{5}{\left(x+y\right)^2}=13\\2x+\frac{1}{x+y}=1\end{matrix}\right.\)
Giải hệ phương trình sau:
\(\left\{{}\begin{matrix}\frac{8}{x-3}+\frac{1}{2\left|y\right|-3}=5\\\frac{4}{x-3}+\frac{1}{2\left|y\right|-3}=3\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x^2+x+\frac{1}{y}\left(1+\frac{1}{y}\right)=4\\x^3+\frac{x}{y^2}+\frac{x^2}{y}+\frac{1}{y^3=4}\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x^2+x+\frac{1}{y}\left(1+\frac{1}{y}\right)=4\\x^3+\frac{x}{y^2}+\frac{x^2}{y}+\frac{1}{y^3}=4\end{matrix}\right.\)
8 tháng 12 2019 lúc 16:44
Giải hpt : a) left{{}begin{matrix}left(x^2+y^2right)left(x+y+1right)25left(y+1right)x^2+xy+2y^2+x-8y9end{matrix}right. b) left{{}begin{matrix}x^2+y^2+6xy-frac{1}{left(x-yright)^2}+frac{9}{8}02y-frac{1}{x-y}+frac{5}{4}0end{matrix}right.
c) left{{}begin{matrix}frac{x}{x^2-y}+frac{5y}{x+y^2}45x+y+frac{x^2-5y^2}{xy}5end{matrix}right. d) left{{}begin{matrix}3xy+y+121x9x^2y^2+3xy+1117x^2end{matrix}right.
e) left{{}begin{matrix}xleft(x^2-y^2right)+x^21sqrt{left(x-y^2right)^3}7...
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Giải hpt : a) \(\left\{{}\begin{matrix}\left(x^2+y^2\right)\left(x+y+1\right)=25\left(y+1\right)\\x^2+xy+2y^2+x-8y=9\end{matrix}\right.\) b) \(\left\{{}\begin{matrix}x^2+y^2+6xy-\frac{1}{\left(x-y\right)^2}+\frac{9}{8}=0\\2y-\frac{1}{x-y}+\frac{5}{4}=0\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}\frac{x}{x^2-y}+\frac{5y}{x+y^2}=4\\5x+y+\frac{x^2-5y^2}{xy}=5\end{matrix}\right.\) d) \(\left\{{}\begin{matrix}3xy+y+1=21x\\9x^2y^2+3xy+1=117x^2\end{matrix}\right.\)
e) \(\left\{{}\begin{matrix}x\left(x^2-y^2\right)+x^2=1\sqrt{\left(x-y^2\right)^3}\\76x^2-20y^2+2=\sqrt[3]{4x\left(8x+1\right)}\end{matrix}\right.\)