Giải:
\(\frac{1+3x}{6}-\frac{2+x}{9}=-4+x\)
\(\text{⇔}\frac{3+9x}{18}-\frac{4+2x}{18}=-\frac{72}{18}+\frac{18x}{18}\)
\(\text{⇔}3+9x-4+2x=-72+18x\)
\(\text{⇔}3+9x-4+2x+72-18x=0\)
\(\text{⇔}71-7x=0\)
\(\text{⇔}x=\frac{71}{7}\)
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g) \(\frac{x+2}{98}+\frac{x+4}{96}=\frac{x+6}{94}+\frac{x+8}{92}\)
h) \(\frac{x-12}{77}+\frac{x-11}{78}=\frac{x-74}{15}+\frac{x-73}{16}\)
i) \(\frac{x+\frac{2\left(3-x\right)}{5}}{14}-\frac{5x-4\left(x-1\right)}{24}=\frac{7x+2\frac{9-3x}{5}}{12}+\frac{2}{3}\)
Giải hộ mik cái mn!!
Giải PT sau :
a,\(\frac{3}{4x-20}+\frac{15}{20-2x^2}+\frac{7}{6x+30}=0\)
b,(x2 - 9)(x - 7) = (x + 3)(x2 + 6)
c, 2x3 + 2 - 2x2 = 1
Mn ơi !! Help me ! mình đang cần gấp
a. \(\frac{x-3}{x-2}+\frac{x-2}{x-4}=-1\)
b.\(\frac{x+16}{49}+\frac{x+18}{47}=\frac{x+20}{45}-1\)
c.\(\frac{7x-1}{2}=5+\frac{9-5x}{6}\)
d.\(\frac{3x-9}{x+1}-2=\frac{4x}{x+1}\)
Dạng 1: Phương trình bậc nhất
Bài 1: Giải các phương trình sau :
a) 0,5x (2x - 9) = 1,5x (x - 5)
b) 28 (x - 1) - 9 (x - 2) = 14x
c) 8 (3x - 2) - 14x = 2 (4 - 7x) + 18x
d) 2 (x - 5) - 6 (1 - 2x) = 3x + 2
e) \(\frac{x+7}{2}-\frac{x-3}{5}=\frac{x}{6}\)
f) \(\frac{2x-3}{3}-\frac{5x+2}{12}=\frac{x-3}{4}+1\)
g) \(\frac{x+6}{2}+\frac{2\left(x+17\right)}{2}+\frac{5\left(x-10\right)}{6}=2x+6\)
h) \(\frac{3x+2}{5}-\frac{4x-3}{7}=4+\frac{x-2}{35}\)
i) \(\frac{x-1}{2}+\frac{x+3}{3}=\frac{5x+3}{6}\)
j) \(\frac{x-3}{5}-1=\frac{4x+1}{4}\)
Dạng 2: Phương trình tích
Bài 2: Giải phương trình sau :
a) (x + 1) (5x + 3) = (3x - 8) (x - 1)
b) (x - 1) (2x - 1) = x(1 - x)
c) (2x - 3) (4 - x) (x - 3) = 0
d) (x + 1)2 - 4x2 = 0
e) (2x + 5)2 = (x + 3)2
f) (2x - 7) (x + 3) = x2 - 9
g) (3x + 4) (x - 4) = (x - 4)2
h) x2 - 6x + 8 = 0
i) x2 + 3x + 2 = 0
j) 2x2 - 5x + 3 = 0
k) x (2x - 7) - 4x + 14 = 9
l) (x - 2)2 - x + 2 = 0
Dạng 3: Phương trình chứa ẩn ở mẫu
Bài 3: Giải phương trình sau :
| \(\frac{90}{x}-\frac{36}{x-6}=2\) | \(\frac{3}{x+2}-\frac{2}{x-3}=\frac{8}{\left(x-3\right)\left(x+2\right)}\) |
| \(\frac{1}{x}+\frac{1}{x+10}=\frac{1}{12}\) | \(\frac{1}{2x-3}-\frac{3}{x\left(2x-3\right)}=\frac{5}{x}\) |
| \(\frac{x+3}{x-3}-\frac{1}{x}=\frac{3}{x\left(x-3\right)}\) | \(\frac{3}{4\left(x-5\right)}+\frac{15}{50-2x^2}=\frac{-7}{6\left(x+5\right)}\) |
| \(\frac{3}{x+2}-\frac{2}{x-2}+\frac{8}{x^2-4}=0\) | \(\frac{x}{x+1}-\frac{2x-3}{1-x}=\frac{3x^2+5}{x^2-1}\) |
\(\frac{1+3x}{6}\) - \(\frac{2+x}{9}\) = -4 +x
Bài tập: Giải phương trình
1) 5-3x=6x+7
2)\(\frac{2x}{3}+\frac{2x-1}{6}=4-\frac{x}{3}\)
3) \(\frac{x-1}{x+3}-\frac{x}{x-3}=\frac{4-8x}{x^2-9}\)
bài 1 giải phương trình
a) (2x+3)\(^2\)-3(x-4)(x+4)=\(\left(x-2\right)^2\)+1
b)(3x-2) (9x\(^2\)+6x+4)-(3x-1) (9x\(^2\)+3x+1)=x-4
c)x (x-1) -(x-3) (x+4)=5x
d) (2x+1)(2x-1)=4x(x-7)-3x
bài 2 giải phương trình
a)\(\frac{x}{10}-\left(\frac{x}{30}+\frac{2x}{45}\right)=\frac{4}{5}\)
b)\(\frac{10x-5}{18}+\frac{x+3}{12}=\frac{7x+3}{6}+\frac{12-x}{9}\)
c)\(\frac{10x+3}{8}=\frac{7-8x}{12}\)
d)\(\frac{x+4}{5}-x-5=\frac{x+3}{3}-\frac{x-2}{2}\)
bài 1:giải các phương trình sau:
a/2,3x-2.(0,7+2x)=3,6-1,7x
b/\(\frac{4}{3}\)x-\(\frac{5}{6}\)=\(\frac{1}{2}\)
c/\(\frac{x}{10}\)-(\(\frac{x}{30}\)+\(\frac{2x}{45}\))=\(\frac{4}{5}\)
d/\(\frac{10x+3}{8}\)=\(\frac{7-8x}{12}\)
e/\(\frac{10x-5}{18}\)+\(\frac{x+3}{12}\)=\(\frac{7x+3}{6}\)-\(\frac{12-x}{9}\)
f/\(\frac{x+4}{5}\)-x-5=\(\frac{x+3}{2}\)-\(\frac{x-2}{2}\)
g/\(\frac{2-x}{4}\)=\(\frac{2.\left(x+1\right)}{5}\)-\(\frac{3.\left(2x-5\right)}{10}\)
h/\(\frac{x+2}{3}\)+\(\frac{3.\left(2x-1\right)}{4}\)-\(\frac{5x-3}{6}\)=x+\(\frac{5}{12}\)
bài 2:giải các phương trình sau:
a/5.(x-1).(2x-1)=3.(x+8).(x-1)
b/(3x-2).(x+6).(\(^{x^2}\)+5)=0
c/(3x-2).(9\(^{x^2}\)+6x+4)-(3x-1).(9\(^{x^2}\)-3x+1)=x-4
d/x.(x-1)-(x-3).(x+4)=5x
e/(2x+1).(2x-1)=4x.(x-7)-3x
1. giải pt
a. 5(x-3)-4=2(x-1)+7
b. \(\frac{8x-3}{4}-\frac{3x-2}{2}=\frac{2x-1}{2}+\frac{x+3}{4}\)
c.\(\frac{2\left(x+5\right)}{3}+\frac{x+12}{2}-\frac{5\left(x-2\right)}{6}=\frac{x}{3}+11\)
d. \(\frac{x-10}{1994}+\frac{x-8}{1996}+\frac{x-6}{1998}+\frac{x-4}{2000}+\frac{x-2}{2002}\)\(=\frac{x-2002}{2}+\frac{x-2000}{4}+\frac{x-1998}{6}+\frac{x-1996}{8}+\frac{x-1994}{10}\)
e. \(\frac{x-85}{15}+\frac{x-74}{13}+\frac{x-67}{11}+\frac{x-64}{9}=10\)
