\(\frac{10^3+2.5^3+5^3}{65}=\frac{10^3+5^3.\left(2+1\right)}{65}=\frac{10^3+5^3.3}{65}\)
= \(\frac{10^3+375}{65}=\frac{1375}{65}\)
\(\frac{10^3+2.5^3+5^3}{65}=\frac{1000+2.125+125}{65}=\frac{8.125+2.125+125.1}{65}=\frac{125\left(8+2+1\right)}{65}=\frac{125.11}{65}=\frac{1375}{65}=\frac{275}{13}\)
\(\frac{10^3+2\cdot5^5+5^3}{65}\)
Giúp minh với
\(\frac{\frac{3}{5}\cdot7^2-3,5^6+\frac{3}{5}\cdot3^9}{\frac{3}{4}\cdot7^2-\frac{3}{4}\cdot5^7+\frac{3}{4}\cdot3^9}\)
A=\(\dfrac{2^{30}\cdot5^7+3^{13}\cdot5^{27}}{2^{27}\cdot5^7+2^{10}\cdot5^{27}}\)
M=\(\left(x-4\right)^{\left(x-5\right)^{\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}}}\) tại x=7
Bài 1 :Thực hiện phép tính :
a) M =(\(\frac{-6}{13}+\frac{15}{26}-\frac{47}{39}-\frac{1}{78}\)) : (\(99\frac{17}{65}-100\frac{5}{52}+\frac{1}{130}\))
b) N = \(\frac{(\frac{3}{5}-0,435+\frac{1}{200}):\left(-0,04\right)}{30,75+\frac{1}{12}+3\frac{1}{6}}\)
c) P = (\(\frac{-5}{6}:\frac{-10}{11}\))+\(\frac{\frac{1}{4}+\frac{5}{8}-\frac{7}{13}}{\frac{-2}{12}-\frac{10}{24}+\frac{14}{39}}\)
Bài 2 : Thực hiện phép tính :V
a) P =\(\frac{\frac{1}{5}-\frac{1}{9}+\frac{1}{13}}{\frac{9}{5}-1+\frac{9}{13}}+\frac{\frac{10}{7}-\frac{10}{11}-\frac{10}{17}}{\frac{12}{7}-\frac{12}{11}-\frac{12}{17}}\)
b) Q = \(\frac{\frac{1}{14}-\frac{1}{30}-\frac{1}{46}}{\frac{2}{35}-\frac{2}{75}-\frac{2}{115}}:\frac{\frac{3}{8}-\frac{15}{17}+\frac{30}{31}}{\frac{1}{6}-\frac{20}{51}+\frac{40}{93}}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
tính :
a, \(A=\dfrac{0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{2,75-2,2+\dfrac{11}{7}+\dfrac{11}{13}}\)
b, \(B=\dfrac{2^{12}.13+2^{12}.65}{2^{10}.104}+\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
Tính nhanh nếu có thể
1. \(\dfrac{-1}{24}-[\dfrac{1}{4}-\left(\dfrac{1}{2}-\dfrac{7}{8}\right)]\)
2. \((\dfrac{5}{7}-\dfrac{7}{5})-[\dfrac{1}{2}-(-\dfrac{2}{7}-\dfrac{1}{10})]\)
3.\(\dfrac{1}{3\cdot5}+\dfrac{1}{5\cdot7}+\dfrac{1}{7\cdot9}+.......+\dfrac{1}{2015\cdot2017}\)
Câu 1: Tìm tất cả số tự nhiên n sao cho: \(2^{n+3}.2^n\)
Câu 2: \(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^n\)
Câu 3: So sánh hai biểu thức A và B trong từng trường hợp:
a) A=\(\frac{10^5+1}{10^{16}+1}\) và B=\(\frac{10^{16}+1}{10^{17}+1}\)
b) A=\(\frac{2^{2008}-3}{2^{2007}-1}\) và B=\(\frac{2^{2007}-3}{2^{2006}-1}\)
