Fo 1/4AA 3/4Aa
F3 Aa= \(\dfrac{3}{4}\cdot\dfrac{1}{2^3}=\dfrac{3}{32}\)
=> aa= \(\dfrac{\left(\dfrac{3}{4}-\dfrac{3}{32}\right)}{2}=\dfrac{21}{64}\)
=> AA= \(1-\dfrac{3}{32}-\dfrac{21}{64}=\dfrac{37}{64}\)
F4 tương tự AA= \(\dfrac{77}{128}\), Aa=\(\dfrac{3}{64}\), aa=\(\dfrac{45}{128}\)
F3:37/64AA:3/32Aa:21/64aa....f4:77/128AA:3/64Aa:45/128aa