Giải:
\(E=x^2-3x-15\)
\(\Leftrightarrow E=x^2-2.x.\dfrac{3}{2}+\left(\dfrac{3}{2}\right)^2-\dfrac{69}{4}\)
\(\Leftrightarrow E=\left(x-\dfrac{3}{2}\right)^2-\dfrac{69}{4}\ge-\dfrac{69}{4};\forall x\)
\(\Leftrightarrow E_{Min}=-\dfrac{69}{4}\)
\("="\Leftrightarrow x-\dfrac{3}{2}=0\Leftrightarrow x=\dfrac{3}{2}\)
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