Question

Đốt hoàn toàn 1 hỗn hợp gồm Co, H₂ cần dùng 4,48l O₂ (đktc) sinh ra 3,36l Co₂
Tính %V CO, H₂

Answer 1

PTHH: \(2CO+O_2\rightarrow2CO_2\\ 0,15mol:0,075mol\leftarrow0,15mol\)

\(2H_2+O_2\rightarrow2H_2O\\ 0,25mol:0,125mol\rightarrow0,25mol\)

\(n_{CO_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)

\(n_{O_2}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\)

\(\Leftrightarrow n_{O_2trongpuvoiH_2}=0,2-0,075=0,125\left(mol\right)\)

\(\left\{{}\begin{matrix}V_{O_2}=0,15.22,4=3,36\left(l\right)\\V_{H_2}=0,25.22,4=5,6\left(l\right)\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}\%V_{CO}=\dfrac{3,36}{3,36+5,6}100\%=37,5\%\\\%V_{H_2}=100\%-37,5\%=62,5\%\end{matrix}\right.\)