Vì 1mol chưa 6.10²³ nguyên tử/ phân tử
=> Đây là 1 mol Zn
\(\text{ 2Zn + O2}\rightarrow2ZnO\)
Mol 1 -> 0,5-> 1
\(\text{a, mZnO= 1.(65+16)= 81g}\)
\(\text{b, V O2 = 0,5.22,4= 11,2(l)}\)
2Zn+O2--->2ZnO
a) n\(_{Zn}=\frac{0,6.10^{23}}{6.10^{23}}=0,1\left(mol\right)\)
Theo pthh
n \(_{ZnO}=n_{Zn}=0,1\left(mol\right)\)
m \(_{ZnO}=0,1.81=8,1\left(g\right)\)
b) Theo pthh
n \(_{O2}=\frac{1}{2}n_{Zn}=0,05\left(mol\right)\)
V\(_{O2}=0,05.22,4=1,12\left(l\right)\)