BTNT " C và H" ta có:
\(n_{CH4}+2n_{C2H2}=n_{CO2}=\frac{35,2}{44}\)
\(4n_{CH4}+2n_{C2H2}=2n_{H2}=\frac{16,2}{18}.2\)
\(\Rightarrow\left\{{}\begin{matrix}n_{CH4}=\frac{1}{33}\\n_{C2H2}=\frac{7}{30}\end{matrix}\right.\)
\(\%m_{CH4}=\frac{\frac{1}{3}.16}{\frac{1}{3}.16+\frac{7}{30}.26}.100\%=46,78\%\)