Question

Dot chay hoan toan hh khi gom CO va H2 can dung 10,08 l khi O2 va sau phan ung thu duoc 2,7 g H2O

Hay tinh

a, Thanh phan % moi khi trong hh ban dau

b, VCO2 thu duoc

Answer 1

PTHH: 2CO+O2 \(\rightarrow\)2CO2(1)

2H2 + O2 \(\rightarrow\)2H2O(2)

nO2==0,45 mol

nH2O=\(\dfrac{2,7}{18}\)=0,15mol

Theo PT2: nO2(PT2)=0,5nH2O=0,075mol

=> nO2(PT1)=0,45-0,075=0,375mol

Theo PT1: nCO=2nO2(PT1)=0,75mol

VCO=0,75.22,4=16,8l

Theo PT2: nH2=nH2O=0,15mol

=> VH2=0,15.22,4=3,36l

=> VH2+VCO=3,36+16,8=20,16l

=>%VH2=\(\dfrac{3,36}{20,16}\).100%=16,67%

=>%VCO=100%-16,67%=83,33%

Theo PT2: nCO2=nCO=0,75mol

=> VCO2=0,75,22,4=16,8 l