\(n_{C_4H_8}=\frac{8,96}{22,4}=0,4\left(mol\right)\)
\(C_4H_8+6O_2\underrightarrow{t^o}4CO_2+4H_2O\)
0.4_____2,4_____1,6____1,6 (mol)
\(a=1,6.22,4=35,84\left(l\right)\)
\(m=1,6.18=28,8\left(g\right)\)
\(V_{O_2}=2,4.22,4=53,76\left(l\right)\)
\(\rightarrow V_{O_2}=20\%V\rightarrow V=\frac{V_{O_2}}{20\%}=\frac{53,76}{20\%}=268,8\left(l\right)\)