\(M_A=15.M_{H_2}=15.2=30\left(\dfrac{g}{mol}\right)\\ Đặt:C_aH_b\left(a,b:nguyên,dương\right)\\ n_C=n_{CO_2}=\dfrac{11,2}{22,4}=0,5\left(mol\right)\\ \Rightarrow m_C=0,5.12=6\left(g\right)\\ m_H=7,5-6=1,5\left(g\right)\\ \Rightarrow n_H=\dfrac{1,5}{1}=1,5\left(mol\right)\\ \Rightarrow a:b=0,5:1,5=1:3\\ \Rightarrow CTTQ:\left(CH_3\right)_t\left(t:nguyên,dương\right)\\ \Leftrightarrow15t=30\\ \Leftrightarrow t=2\\ \Rightarrow CTPT:C_2H_6\\ CTCT:CH_3-CH_3\)