\(PTHH:4P+5O_2-^{t^o}>2P_2O_5\)
0,2--->0,25----->0,1 (mol)
\(n_P=\dfrac{m}{M}=\dfrac{6,2}{31}=0,2\left(mol\right)\)
\(V_{O_2\left(dktc\right)}=n\cdot22,4=0,25\cdot22,4=5,6\left(l\right)\)
\(m_{P_2O_5}=n\cdot M=0,1\cdot\left(31\cdot2+16\cdot5\right)=14,2\left(g\right)\)