\(n_S=\frac{4,8}{32}=0,15\left(mol\right)\)
\(PTHH:S+O_2\underrightarrow{t^o}SO_2\)
(mol)____0,15_______0,15__
\(n_{NaOH}=0,2.2=0,4\left(mol\right)\)
Tỉ lệ: \(\frac{n_{OH}}{n_{SO_2}}=\frac{0,4}{0,15}=2,7>2\rightarrow\) Tạo muối trung hòa, tính theo \(SO_2\)
\(PTHH:2NaOH+SO_2\rightarrow Na_2SO_3+H_2O\)
(mol)______0,3_______0,15_____0,15___________
Sau pứ có \(0,15(mol)Na_2SO_3\) và \(0,4-0,3=0,1\left(mol\right)NaOH\)
\(C_{M_{Na_2SO_3}}=\frac{0,15}{0,2}=0,75\left(M\right)\)
\(C_{M_{NaOH}}=\frac{0,1}{0,2}=0,5\left(M\right)\)