a, \(C_2H_4+3O_2\rightarrow2CO_2+2H_2O\)
\(2C_3H_6+9O_2\rightarrow6CO_2+6H_2O\)
Ta có :
\(n_{CO2}=\frac{8,96}{22,4}=0,4\left(mol\right)\)
\(n_{hh}=\frac{3,36}{22,4}=0,15\left(mol\right)\)
Gọi \(\left\{{}\begin{matrix}n_{C2H4}:a\left(mol\right)\\n_{C3H6}:b\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}a+b=0,15\\2a+3b=0,4\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,05\\b=0,1\end{matrix}\right.\)
\(\%_{C2H4}=\frac{0,05}{0,15}.100\%=33,33\%\)
\(\%_{C3H6}=100\%-33,33\%=66,67\%\)
b,\(n_{H2O}=n_{CO2}=0,4\left(mol\right)\)
\(m=m_{H2O}=0,4.18=7,2\left(g\right)\)
