CTTQ:CxHy
\(n_{C_xH_y}=\frac{2,24}{22,4}=0,1\left(mol\right)\)
\(n_{CaCO_3}=\frac{10}{100}=0,1\left(mol\right)\)
\(2C_xH_y+\frac{4x+y}{2}O_2\rightarrow2xCO_2+yH_2O\)
0,1.................................0,1x
\(CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3\downarrow+H_2O\)
0,1......................................0,1
=> 0,1x=0,1 => x = 1
=> CH4.................A