\(m_C=1000.96\%=960\left(g\right)\) => \(n_C=\frac{960}{12}=80\left(mol\right)\)
\(m_S=1000.2\%=20\left(g\right)\) => \(n_S=\frac{20}{32}=0,625\left(mol\right)\)
PTHH: C + O2 --> CO2 (1)
80 -> 80 -> 80 (mol)
S + O2 --> SO2 (2)
0,625 -> 0,625 -> 0,625 (mol)
=> \(n_{O2}=80+0,625=80,625\left(mol\right)\)
=> \(n_{O2}=80,625.22,4=1806\left(l\right)\)
b) \(m_{CO2}=80.44=3520\left(g\right)\)
\(m_{SO2}=0,625.64=40\left(g\right)\)
a,
Trong 1kg = 1000g than có 960g C; 20g S
\(\rightarrow n_C=80\left(mol\right),n_S=0,625\left(mol\right)\)
\(C+O_2\underrightarrow{^{to}}CO_2\)
\(S+O_2\underrightarrow{^{to}}SO_2\)
\(\rightarrow n_{O2}=n_S+n_C=80,625\left(mol\right)\)
\(\rightarrow V_{O2}=18061\left(l\right)\)
b,
\(n_C=n_{CO2}\rightarrow m_{CO2}=3520\left(g\right)\)
\(n_S=n_{SO2}\rightarrow m_{SO2}=1280\left(g\right)\)
