\(CH4+2O2-->CO2+2H2O\)
x-------------------------x(mol)
\(C2H2+\frac{5}{2}O2-->2CO2+H2O\)
y-------------------------------2y(mol)
\(CO2+Ca\left(OH\right)2-->CaCO3+H2O\)
\(n_{CaCO3}=\frac{60}{100}=0,6\left(mol\right)\)
\(n_{CO2}=n_{CaCO3}=0,6\left(mol\right)\)
\(n_{hh}=\frac{11.2}{224}=0,5\left(mol\right)\)
Theo bài ta có hpt
\(\left\{{}\begin{matrix}x+y=0,5\\x+2y=0,6\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,4\\y=0,1\end{matrix}\right.\)
\(\%n_{CH4}=\frac{0,4}{0,5}.100\%=80\%\)
\(\%n_{C2H2}=100-80=20\%\)
