mC = 1.1 x 12/44 = 0.3 (g)
mH = 0.45 x 2/18 = 0.05 (g)
Theo ĐLBTKL: ==> mA = 1.1 + 0.45 - 0.8 = 0.75 (g)
mO = 0.75 -(0.3 +0.05) = 0.4 (g)
Với 3.2 g oxi => nO2 = 0.1 (mol) => VO2 = 2.24 (l)
6g A ----> 2.24 (l); 0.75gA ----> 0.28 (l)
nA = 0.0125 (mol) ==> A = 0.75/0.0125 = 60
CxHyOz
12x/0.3 = y/0.05 = 16z/0.4 = 60/0.75
Suy ra: x = 2, y = 4; z = 2
CT: C2H4O2