S+O2--->SO2
a) n S=1,6/32=0,05(mol)
n O2=11,2/22,4=0,5(mol)
-->O2 dư
n O2 dư=0,5-0,05=0,45(mol)--->m O2 dư=0,45.32=14,4(g)
n SO2=n S=0,05(mol)
m S=0,05.64=3,2(g)
n hh=0,45+0,05=0,5(mol)
m hh=14,4+3,2=17,6(g)
% thể tích=% số mol
%V O2 dư=%n O2 dư=0,45/0,5.100%=90%
%V SO2=%n SO2=10%
%m O2=14,4/17,6.100%=81,82%
%m SO2=100%-81,82=18,18%