\(\dfrac{x+1}{99}+\dfrac{x+2}{98}+\dfrac{x+3}{97}+\dfrac{x+4}{96}=-4\)
\(\Leftrightarrow\dfrac{x+1}{99}+1+\dfrac{x+2}{98}+1+\dfrac{x+3}{97}+1+\dfrac{x+4}{96}+1=0\)
\(\dfrac{x+100}{99}+\dfrac{x+100}{98}+\dfrac{x+100}{97}+\dfrac{x+100}{96}=0\)
\(\Rightarrow x+100=0\Leftrightarrow x=-100\) vậy \(x=-100\)
Tính \(H=\dfrac{\dfrac{1}{99}+\dfrac{2}{98}+\dfrac{3}{97}+...........+\dfrac{99}{1}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+.............+\dfrac{1}{100}}:\dfrac{92-\dfrac{1}{9}-\dfrac{1}{10}-..............\dfrac{92}{100}}{\dfrac{1}{45}+\dfrac{1}{50}+\dfrac{1}{55}+........+\dfrac{1}{500}}\)
Help me!!!
BT3: Tìm x, biết
3) \(\dfrac{3}{4}.x-\dfrac{5}{3}.x=\dfrac{7}{12}\)
4) \(x-\dfrac{1}{7}=\) \(\dfrac{\dfrac{4}{2011}-\dfrac{4}{2013}+\dfrac{4}{99}}{\dfrac{5}{2011}-\dfrac{5}{2013}+\dfrac{5}{99}}+\dfrac{1}{2}\)
Các bạn giúp mk nhé
BT1: Tính nhanh:
3) ( \(\dfrac{98}{99}-\dfrac{98}{97}+\dfrac{1}{97.98}\) ) . ( \(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}\))
Cho M = \(\dfrac{1+2+3}{4}+\dfrac{4+5+6}{8}+......+\dfrac{97+98+99}{100}\)
N = 1 + \(\dfrac{1}{2}+\dfrac{1}{3}+.......+\dfrac{1}{25}\)
Tính \(\dfrac{M}{50-N}\) ????
Thánh nào đi quá có tâm làm hộ đi , pờ li T.T
BT2: Tính nhanh
11) \(\left(\dfrac{99}{98}-\dfrac{98}{97}+\dfrac{1}{98.97}\right).\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}\right)\)
12) \(\dfrac{7}{17}+\dfrac{10}{17}\left(\dfrac{-3}{5}+\dfrac{1}{2}\right)^2\)
\(\dfrac{48}{25}\)x\(\dfrac{27}{55}\) +2\(\dfrac{4}{9}\)x\(\dfrac{14}{33}\)
1\(\dfrac{19}{22}\)x(\(\dfrac{47}{77}\)-\(\dfrac{16}{55}\))
(3\(\dfrac{10}{99}\)+4\(\dfrac{11}{99}\)-5\(\dfrac{8}{299}\))-(\(\dfrac{1}{2}\)-\(\dfrac{1}{3}\)-\(\dfrac{1}{6}\))
đề bài là thực hiện phép tính
Bài 1. Tính giá trị biểu thức
125%.\((\dfrac{-1}{2})^2\):\((1\dfrac{5}{16}-1,5)+2008^0\)
\(\dfrac{2}{3.5}+\dfrac{2}{5.3}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}+\dfrac{2}{13.15}\)
Bài 2. Tìm x, biết
x:\(3\dfrac{1}{15}=1\dfrac{1}{12}\)
\(\dfrac{3}{4}.x=27\)
\(x.\dfrac{1}{4}=\dfrac{5}{8}.\dfrac{2}{3}\)
\(\left(x+\dfrac{1}{4}\right):\dfrac{3}{7}=\dfrac{1}{6}\)
\(\dfrac{3}{4}-2.|2x-\dfrac{2}{3}|=2\)
\(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{2}\)
BT2: Tìm x, biết
3) \(\dfrac{1}{2}.\left(x-\dfrac{1}{3}\right)=\dfrac{1}{3}.\left(x-\dfrac{1}{4}\right)\)
4) \(\text{ | }x-\dfrac{1}{3}\text{\text{ |}}-\dfrac{1}{3}=\dfrac{1}{3}\)
\(\dfrac{-3}{4}x\dfrac{4}{7}+\dfrac{-3}{5}x\dfrac{3}{7}-\dfrac{2}{5}\)
\(\left(\dfrac{3}{4}x\dfrac{5}{6}-\dfrac{7}{12}\right)x\left(\dfrac{-12}{7}\right)\)
\(1,4x\dfrac{15}{19}x\left(\dfrac{4}{5}x\dfrac{-2}{3}\right)+\dfrac{7}{15}\)
Tính nha
