Question

\(\dfrac{x-3}{5}=\dfrac{5-2x}{-11}\)

Tìm x?

Answer 1

\(\dfrac{x-3}{5}=\dfrac{5-2x}{-11}\)

\(\Rightarrow-11\left(x-3\right)=5\left(5-2x\right)\)

\(\Leftrightarrow-11x+33=25-10x\)

\(\Leftrightarrow x=8\)

Vậy x = 8

Answer 2

\(\dfrac{x-3}{5}\)=\(\dfrac{5-2x}{-11}\)

⇒\(-11(x-3)\)=\(5(5-2x)\)

⇔\(-11x+33\)=\(25-10x\)

⇔\(-11x+10x\)=\(25-33\)

⇔\(-x=-8\)

⇒\(x=8\)

Answer 3

 

<=> (x-3).11= (5-2x).5

<=>   11x -33 -  25 +10x =0

<=>  21x = 58 

<=>  x = 58/21