ĐKXĐ: x > 1
\(\dfrac{\left(\dfrac{1}{\sqrt{x-1}}+\dfrac{1}{\sqrt{x+1}}\right)}{\left(\dfrac{1}{\sqrt{x-1}}-\dfrac{1}{\sqrt{x+1}}\right)}=\dfrac{\dfrac{\sqrt{x+1}+\sqrt{x-1}}{\sqrt{x^2-1}}}{\dfrac{\sqrt{x+1}-\sqrt{x-1}}{\sqrt{x^2-1}}}=\dfrac{\sqrt{x+1}+\sqrt{x-1}}{\sqrt{x+1}-\sqrt{x-1}}=\dfrac{\left(\sqrt{x+1}+\sqrt{x-1}\right)^2}{2}\)