\(VT=91\left(\dfrac{1}{1\cdot4}+\dfrac{1}{4\cdot7}+...+\dfrac{1}{88\cdot91}\right)\)
\(=\dfrac{91}{3}\cdot\left(\dfrac{3}{1\cdot4}+\dfrac{3}{4\cdot7}+...+\dfrac{3}{88\cdot91}\right)\)
\(=\dfrac{91}{3}\cdot\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{88}-\dfrac{1}{91}\right)\)
\(=\dfrac{91}{3}\cdot\dfrac{90}{91}=30\)
5\(\dfrac{8}{17}\): x + (-\(\dfrac{1}{17}\)) : x + 3\(\dfrac{1}{17}\): 17\(\dfrac{1}{3}\)= \(\dfrac{4}{17}\)
\(\dfrac{1}{1.4}\)+ \(\dfrac{1}{4.7}\)+ \(\dfrac{1}{7.10}\)+ ... + \(\dfrac{1}{x.\left(x+3\right)}\)= \(\dfrac{6}{19}\)
So sánh hai biểu thức A và B, biết rằng:
A = \(\dfrac{2012}{2013}\)+ \(\dfrac{2013}{2014}\) và B =\(\dfrac{2012+2013}{2013+2014}\).
Thực hiện phép tính : \(\dfrac{3}{2}-\dfrac{5}{6}-\dfrac{9}{20}-\dfrac{13}{42}+\dfrac{11}{30}+\dfrac{15}{56}+\dfrac{7}{12}\)
a) \(\dfrac{2}{1^2}.\dfrac{6}{2^2}.\dfrac{12}{3^2}.\dfrac{20}{4^2}.\dfrac{30}{5^2}.....\dfrac{110}{10^2}.x=-20\)
b) \(\left(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2013}\right).x+2013=\dfrac{2014}{1}+\dfrac{2015}{2}+...+\dfrac{4025}{2012}+\dfrac{4026}{2013}\)
c) \(\left(\dfrac{1}{1.2}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right).x=\dfrac{2012}{51}+\dfrac{2012}{52}+...+\dfrac{2012}{99}+\dfrac{2012}{100}\)
Tính tổng M = \(\dfrac{1}{4^2-1}+\dfrac{1}{6^2-1}+\dfrac{1}{8^2-1}+...+\dfrac{1}{30^2-1}\)
Tính nhanh
\(\dfrac{15}{56}\) - \(\dfrac{13}{42}\) + \(\dfrac{11}{30}\) - \(\dfrac{9}{20}\) + \(\dfrac{7}{12}\) - \(\dfrac{5}{6}\) +\(\dfrac{3}{2}\)
Tìm giá trị biểu thức:
a) P=\(\dfrac{5}{6}\)+\(\dfrac{5}{12}\)+\(\dfrac{5}{20}\)+\(\dfrac{5}{30}\)+\(\dfrac{5}{42}\)+\(\dfrac{5}{56}\)+\(\dfrac{5}{72}\)+\(\dfrac{5}{90}\)
b) A=\(\dfrac{3}{1.5}\)+\(\dfrac{3}{5.9}\)+\(\dfrac{3}{9.13}\)+...+\(\dfrac{3}{61.65}\). Chứng minh A<13.
Mik đag cần gấppp!!! Thanks!
Bài 1: Tìm a , b , c , d \(\in\) N , biết :
\(\dfrac{30}{43}\) = \(\dfrac{1}{a+\dfrac{1}{b+\dfrac{1}{c+\dfrac{1}{d}}}}\)
Tính
A=1+2+3+4+5+.....+99+100
B= \(\dfrac{1}{2}\)+ \(\dfrac{1}{6}\)+\(\dfrac{1}{12}\)+\(\dfrac{1}{20}\)+ \(\dfrac{1}{30}\)+....+\(\dfrac{1}{9900}\)
Tính tổng:
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{97.100}\)
