\(\dfrac{6^3+3.6^2+3^3}{-13}\)=\(\dfrac{3^3.2^3+3.2^2.3^2+3^3}{-13}\)=\(\dfrac{3^3\left(2^3+2^2+1\right)}{-13}\)
=\(\dfrac{3^3.13}{-13}\)=\(-3^3\)=\(-27\)
\(\dfrac{6^2+3\cdot6^2+3^2}{-13}\)
Tính nhanh
\(\dfrac{\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}}{\dfrac{2}{3}-\dfrac{2}{7}-\dfrac{2}{13}}\cdot\dfrac{\dfrac{1}{3}-0,25+0,2}{1\dfrac{1}{6}-0,875+0,7}+\dfrac{6}{7}\)
Tinh:
\(\dfrac{-3}{5}.51\dfrac{11}{13}+\dfrac{3}{5}.21\dfrac{11}{13}\)
\(\left|\dfrac{-3}{4}\right|.\left|-\dfrac{2}{3}\right|\)
\(\dfrac{-3}{5}+5\dfrac{1}{13}-\dfrac{2}{3}+1\dfrac{3}{5}-\dfrac{11}{33}\)
\(\dfrac{3}{4}.\sqrt{16}-10.\sqrt{0,81}\)
\(\left(\dfrac{3}{4}\right)^3:\left(-\dfrac{3}{8}\right)^3\)
\(\dfrac{6^4.15^3}{8.9^3.10^3}\)
GIUP MK T ^ T
Tinh
a) \(\left(-1,25\right).14,7.\left(-8\right)\)
b)\(\dfrac{3}{4}-1\dfrac{1}{6}\)
c)\(\dfrac{-3}{5}.51\dfrac{11}{13}+\dfrac{3}{5}.21\dfrac{11}{13}\)
d)\(\left|\dfrac{-3}{4}\right|.\left|-\dfrac{2}{3}\right|\)
e)\(\dfrac{-3}{5}+5\dfrac{1}{13}-\dfrac{2}{3}+1\dfrac{3}{5}-\dfrac{11}{33}\)
f)\(\dfrac{3}{4}.\sqrt{16}-10.\sqrt{0,81}\)
g)\(\left(\dfrac{3}{4}\right)^3:\left(-\dfrac{3}{8}\right)^3\)
h)\(\dfrac{6^4.15^3}{8.9^3.10^3}\)
GIUP MK T ^ T
Tính
A=\(\dfrac{\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{13}}{\dfrac{2}{3}-\dfrac{2}{7}-\dfrac{2}{13}}.\dfrac{\dfrac{3}{4}-\dfrac{3}{16}-\dfrac{3}{64}-\dfrac{3}{256}}{1-\dfrac{1}{4}-\dfrac{1}{16}-\dfrac{1}{64}}+\dfrac{5}{8}\)
tính \(\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{11}}{\dfrac{13}{4}-\dfrac{13}{5}+\dfrac{13}{7}+\dfrac{13}{11}}\)
thực hiện phép tính:
a,\(\left(\dfrac{2}{3}\right)^3-\left(\dfrac{3}{4}\right)^2.\left(-1\right)^5\)
b,\(12:\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)
c,\(\dfrac{7}{22}:\dfrac{3}{11}+\dfrac{7}{22}:\dfrac{4}{11}\)
d,\(\dfrac{12}{35}.\left(\dfrac{7}{4}+\dfrac{13}{4}\right)-\dfrac{1}{3}\)
Giúp mk với
Bài 1:
a) A=\(\dfrac{\dfrac{3}{4}-\dfrac{3}{11}+\dfrac{3}{13}}{\dfrac{5}{7}-\dfrac{5}{11}+\dfrac{5}{13}}\) + \(\dfrac{\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}}{\dfrac{5}{4}-\dfrac{5}{6}+\dfrac{5}{8}}\)
b) Cho 3 số x, y, z là 3 số khác 0 thoả mãn điều kiện: \(\dfrac{y+z-x}{x}\) = \(\dfrac{z+x-y}{y}\) = \(\dfrac{x+y-z}{z}\)
Hãy tính giá trị biểu thức: B=(1+\(\dfrac{x}{y}\)) (1+\(\dfrac{y}{z}\)) (1+\(\dfrac{z}{x}\))
a) A= \(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{72}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
b) B=\(\dfrac{1}{5}-\dfrac{3}{7}+\dfrac{5}{9}-\dfrac{2}{9}+\dfrac{7}{13}-\dfrac{2}{11}-\dfrac{5}{9}+\dfrac{3}{7}-\dfrac{1}{5}\)
c) C=\(\dfrac{1}{100}-\dfrac{1}{100.99}-\dfrac{1}{99.98}-\dfrac{1}{98.97}-......-\dfrac{1}{3.2}-\dfrac{1}{2.1}\)
