Question

\(\dfrac{2x-1}{3}\)=x-1

Answer 1

\(\dfrac{2x-1}{3}=x-1\)

=> \(2x-1=3x-3\)

=> \(2x-1-3x+3=0\)

=> \(-x+2=0\)

=> \(-x=-2\)

=> \(x=2\)

Vậy \(x=2\)

Answer 2

\(\dfrac{2x-1}{3}=x-1\)

\(\Leftrightarrow2x-1=3\left(x-1\right)\)

\(\Leftrightarrow2x-1=3x-3\)

\(\Leftrightarrow2x-1-3x+3=0\)

\(\Leftrightarrow-x+2=0\Leftrightarrow-x=-2\Rightarrow x=2\)

Answer 3

Ta có:\(\dfrac{2x-1}{3}\)=x-1<=>2x-1=3(x-1)

<=>2x-1=3x-3<=>3x-2x=-1+3<=>x=2

Vậy S={2}

Answer 4

\(\dfrac{2x-1}{3}=x-1\)

\(\Leftrightarrow\dfrac{2x-1}{3}=\dfrac{3\left(x-1\right)}{3}\)

\(\Rightarrow2x-1=3x-3\)

\(\Leftrightarrow2x-3x=-3+1\)

\(\Leftrightarrow-x=-2\Rightarrow x=2\)

Answer 5

\(\dfrac{2x-1}{3}=x-1\)

\(\Leftrightarrow2x-1=3x-3\)

\(\Leftrightarrow x=2\)

Vậy.....

Answer 6

<=> \(2x-1=3x-3\)

<=> \(2x-3x=-3+1\)

<=> \(-x=-2\)

<=> \(x=2\)

Vậy \(x=2\)

Answer 7

\(\dfrac{2x-1}{3}=x-1\)

\(\Leftrightarrow2x-1=3\left(x-1\right)\)

\(\Leftrightarrow2x-1=3x-3\)

\(\Leftrightarrow2x=3x-3+1\)

\(\Leftrightarrow2x=3x-2\)

\(\Leftrightarrow x=2\)