Question

\(\dfrac{2}{3}\)-(\(\dfrac{1}{6}\)+\(\dfrac{1}{8}\))

Answer 1

\(\dfrac{2}{3}-\left(\dfrac{1}{6}+\dfrac{1}{8}\right)=\dfrac{2}{3}-\dfrac{7}{24}=\dfrac{3}{8}\)

Answer 2

\(\dfrac{2}{3}-\left(\dfrac{1}{6}+\dfrac{1}{8}\right)=\dfrac{2}{3}-\dfrac{7}{24}=\dfrac{16}{24}-\dfrac{7}{24}=\dfrac{9}{24}=\dfrac{3}{8}\)

Answer 3

\(=\dfrac{2}{3}-\left(\dfrac{8+6}{48}\right)=\dfrac{2}{3}-\dfrac{7}{24}=\dfrac{2.8}{3.8}-\dfrac{7}{24}=\dfrac{16}{24}-\dfrac{7}{24}=\dfrac{16-7}{24}=\dfrac{9}{24}=\dfrac{3}{8}\)

Answer 4

= \(\dfrac{2}{3}\) - \(\dfrac{14}{48}\)

= \(\dfrac{16}{24}-\dfrac{7}{24}\)

= \(\dfrac{9}{24}\) = \(\dfrac{3}{8}\)