Question

\(-\dfrac{15}{12}x+\dfrac{3}{7}=\dfrac{6}{5}x-\dfrac{1}{2}\)

Answer 1

\(-\dfrac{15}{12}x+\dfrac{3}{7}=\dfrac{6}{5}x-\dfrac{1}{2}\\ \Rightarrow-\dfrac{15}{12}x-\dfrac{6}{5}x=\dfrac{1}{2}-\dfrac{3}{7}\\ \Rightarrow\left(-\dfrac{15}{12}-\dfrac{6}{5}\right)x=\dfrac{1}{14}\\ \Rightarrow-\dfrac{49}{20}x=\dfrac{1}{14}\\ \Rightarrow x=\dfrac{1}{14}:\left(-\dfrac{49}{20}\right)\\ \Rightarrow x=-\dfrac{10}{343}\)

Vậy tập nghiệm phương trình x là \(\left\{-\dfrac{10}{343}\right\}\)

Answer 2

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