Question

\(\dfrac{-2}{5}-\dfrac{3}{5}-\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{4}{9}\)

Answer 1

\(-\dfrac{2}{5}-\dfrac{3}{5}-\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{4}{9}\\ =\left(\dfrac{-2-3-2-3}{5}\right)+\dfrac{4}{9}\\ =-2+\dfrac{4}{9}\\ =-\dfrac{14}{9}\)

Answer 2

\(\dfrac{-2}{5}-\dfrac{3}{5}-\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{4}{9}\)

= \(\left(\dfrac{-2}{5}-\dfrac{3}{5}-\dfrac{2}{5}-\dfrac{3}{5}\right)+\dfrac{4}{9}\)

= \(-2+\dfrac{4}{9}\)

= \(\dfrac{-14}{9}\)

Answer 3

\(\dfrac{-2}{5}-\dfrac{3}{5}-\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{4}{9}\)

= \(\left(\dfrac{-2}{5}-\dfrac{2}{5}-\dfrac{3}{5}-\dfrac{3}{5}\right)+\dfrac{4}{9}\)

= \(-2+\dfrac{4}{9}\)

= \(\dfrac{-14}{9}\)

Answer 4

\(\dfrac{-2}{5}-\dfrac{3}{5}-\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{4}{9}\)

\(=\dfrac{-2-3-2-3}{5}+\dfrac{4}{9}\)

\(=\dfrac{-10}{5}+\dfrac{4}{9}=-2+\dfrac{4}{9}=\dfrac{-18}{9}+\dfrac{4}{9}=\dfrac{-18+4}{9}=\dfrac{-14}{9}\)

Answer 5

\(\dfrac{-2}{5}-\dfrac{3}{5}-\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{4}{9}=\dfrac{-2-3-2-3}{5}+\dfrac{4}{9}\)

\(=\dfrac{-10}{5}+\dfrac{4}{9}=-2+\dfrac{4}{9}=\dfrac{-18}{9}+\dfrac{4}{9}=\dfrac{-18+4}{9}=\dfrac{-14}{9}\)