\(n_{CH_3COOH}=\frac{100.6}{100.60}=0,1\left(mol\right)\)
\(PTHH:NaHCO_3+CH_3COOH\rightarrow CH_3COONa+H_2O+CO_2\)
(mol)_______0,1__________0,1_______________0,1_____________0,1_
\(m_{NaHCO_3}=84.0,1=8,4\left(g\right)\)
\(V_{CO_2}=22,4.0,1=2,24\left(l\right)\)
\(PTHH:C_6H_{12}O_6\xrightarrow[30-35^oC]{men.r\text{ượu}}2C_2H_5OH+2CO_2\)
(mol)_____0,05_______________0,1_________0,1_
Do \(H=90\%\Rightarrow n_{C_6H_{12}O_6\left(tt\right)}=\frac{0,05.100}{90}=\frac{1}{18}\left(mol\right)\)
\(m_{C_6H_{12}O_6}=\frac{1}{18}.180=10\left(g\right)\)
@Lê Thu Dương @Nguyễn Trần Thành Đạt @buithianhtho giúp e với