\(n_{H2S}=0,1\left(mol\right)\)
\(2NaOH+H_2S\rightarrow Na_2S+2H_2O\)
\(NaOH+H_2S\rightarrow NaHS+H_2O\)
- TH1: \(n_{NaOH}=0,5.0,1=0,05\left(mol\right)\)
\(\Rightarrow\) Dư H2S. Tạo 0,05 mol NaHS
\(CM_{NaHS}=0,1M\)
- TH2: \(n_{NaOH}=0,1\left(mol\right)\)
\(\Rightarrow\) Tạo 0,1 mol NaHS
\(CM_{NaHS}=0,2M\)
- TH3: \(n_{NaOH}=0,15\left(mol\right)\)
\(\Rightarrow\) Tạo 0,05 mol Na2S, 0,05 mol NaHS
\(CM_{Na2S}=NaHS=0,1M\)
- TH4: \(n_{NaOH}=0,2\left(mol\right)\)
\(\Rightarrow\) Tạo 0,1 mol Na2S
\(CM_{Na2S}=0,2M\)
- TH5: \(n_{NaOH}=0,25\left(mol\right)\)
\(\Rightarrow\) Dư 0,05 NaOH. Tạo 0,1 mol Na2S
\(\Rightarrow\left\{{}\begin{matrix}CM_{NaOH}=0,1M\\CM_{Na2S}=0,2M\end{matrix}\right.\)
