Sửa đề: \(D=\dfrac{\dfrac{12}{19}-12+\dfrac{12}{47}}{\dfrac{6}{19}-6+\dfrac{6}{47}}=\dfrac{12\left(\dfrac{1}{19}-1+\dfrac{1}{47}\right)}{6\left(\dfrac{1}{19}-1+\dfrac{1}{47}\right)}=2\)
Sửa đề: \(D=\dfrac{\dfrac{12}{19}-12+\dfrac{12}{47}}{\dfrac{6}{19}-6+\dfrac{6}{47}}=\dfrac{12\left(\dfrac{1}{19}-1+\dfrac{1}{47}\right)}{6\left(\dfrac{1}{19}-1+\dfrac{1}{47}\right)}=2\)
\(\dfrac{\dfrac{3}{41}-\dfrac{12}{47}+\dfrac{27}{53}}{\dfrac{4}{41}-\dfrac{16}{47}+\dfrac{36}{53}}+\)
đề bài là \(Tính\)
tính nhanh nếu có thể:
a)\(\dfrac{4}{2.4}+\dfrac{4}{4.6}+\dfrac{4}{6.8}+.....+\dfrac{4}{2008.2010}\)
b)\(\dfrac{\dfrac{3}{41}-\dfrac{12}{47}+\dfrac{27}{53}}{\dfrac{4}{41}-\dfrac{16}{47}+\dfrac{36}{53}}\)
1 tinh
a,\(5\dfrac{4}{23}.27\dfrac{3}{47}+4\dfrac{3}{47}.\left(-5\dfrac{4}{23}\right)\)
b,4.\(\left(\dfrac{-1}{2}\right)^3+\dfrac{3}{2}\)
c,\(\left(\dfrac{1999}{2011}-\dfrac{2011}{1999}\right)-\left(\dfrac{-12}{1999}-\dfrac{12}{2011}\right)\)
d,\(\left(\dfrac{-5}{11}+\dfrac{7}{22}-\dfrac{-4}{33}-\dfrac{5}{44}\right):\left(\dfrac{381}{22}-39\dfrac{7}{22}\right)\)
bài 1 so sánh
a) \(\dfrac{45}{105}va\dfrac{84}{147}\)
b) \(\dfrac{-12}{19}va\dfrac{-14}{17}\)
c) \(\dfrac{13}{19}va\dfrac{47}{53}\)
d) \(\dfrac{-29}{38}va\dfrac{-13}{22}\)
\(1\dfrac{13}{15}.0,75-\left(\dfrac{8}{15}+25\%\right).\dfrac{24}{47}-3\dfrac{12}{13}:3\)
Bài 1: Tính ( hợp lý nếu có thể)
A=\(\dfrac{-3}{8}\)+\(\dfrac{12}{25}\)+\(\dfrac{5}{-8}\)+\(\dfrac{2}{-5}\)+\(\dfrac{13}{25}\)
B=\(\dfrac{-3}{15}\)+(\(\dfrac{2}{3}\)+\(\dfrac{3}{15}\))
C=\(\dfrac{-5}{21}\)+(\(\dfrac{-16}{21}\)+1)
D=(\(\dfrac{-1}{6}\)+\(\dfrac{5}{-12}\))+\(\dfrac{7}{12}\)
E=\(\dfrac{1}{3}\)x\(\dfrac{4}{5}\)+\(\dfrac{1}{3}\)x\(\dfrac{6}{5}\)+\(\dfrac{2}{3}\)
F=\(\dfrac{-5}{6}\)x\(\dfrac{4}{19}\)+\(\dfrac{-7}{12}\)x\(\dfrac{4}{12}\)-\(\dfrac{40}{47}\)
Bài 2: Tìm x,biết:
a) x + \(\dfrac{2}{3}\) = \(\dfrac{4}{5}\)
b) x - \(\dfrac{2}{3}\) = \(\dfrac{7}{21}\)
c) -x - \(\dfrac{3}{4}\) =\(\dfrac{-8}{11}\)
d) \(\dfrac{11}{12}\) - (\(\dfrac{2}{5}\) + x) = \(\dfrac{2}{3}\)
\(\dfrac{-5}{9}+1\dfrac{5}{9}\cdot\left(\dfrac{3}{4}-\dfrac{2}{5}\right):7^2\)
\(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{104}{195}+25\%\right)\cdot\dfrac{24}{47}-3\dfrac{12}{13}:3\)
\(1\dfrac{13}{15}\cdot\left(0,5\right)^2\cdot3+\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
Rút gọn các biểu thức sau;
\(\dfrac{-5}{12}.\dfrac{2}{7}+\dfrac{7}{12}.\dfrac{-3}{14}\)
b)\(\dfrac{2.\left(-13\right).9.10}{\left(-3\right).4.\left(-5\right).26}\)
c) 1.\(\dfrac{13}{15}-0,75-\)(\(\dfrac{104}{195}+25\%\)).\(\dfrac{24}{47}-3\dfrac{12}{13}:3\)
Bài tập: So sánh:
a, \(\dfrac{12}{49}\&\dfrac{13}{47}\)
\(b,\dfrac{64}{85}\&\dfrac{17}{35}\)
\(c,\dfrac{19}{31}\&\dfrac{17}{35}\)
(Gợi ý: a,b,c: Phân số chung gian)
\(d,\dfrac{67}{77}\&\dfrac{73}{83}\)
\(e,\dfrac{456}{461}\&\dfrac{123}{128}\)
(Gợi ý: d, e:Phần bù đến đơn vị)