Ta có:
\(\dfrac{11}{2}.\dfrac{12}{2}.\dfrac{13}{2}.....\dfrac{20}{2}\\ =\dfrac{11.12.13.....20}{2^{10}}\\ =\dfrac{\left(11.12.13.....20\right)\left(1.2.3.....10\right)}{2^{10}\left(1.2.3.....10\right)}\\ =\dfrac{1.2.3.4.....20}{2.4.6.8.....20}\\ =\dfrac{\left(1.3.5.7.....19\right)\left(2.4.6.....20\right)}{\left(2.4.6.....20\right)}\\ =1.3.5.7.....19\)
=> Đpcm