Question

Chứng tỏ rằng :

a) \(0,\left(37\right)+0,\left(62\right)=1\)

b) \(0,\left(33\right).3=1\)

Answer 1

a)ta có: 0, (37) + 0, (62) = 1

\(\Rightarrow\)\(\dfrac{37}{99}+\dfrac{62}{99}=1\left(ĐPCM\right)\)

b)ta có: 0, (33).3=1

\(\Rightarrow\)\(\dfrac{1}{3}.3=1\left(ĐPCM\right)\)

Answer 2

a) Ta có:

0, (37) = 0, (01) . 37 = \(\dfrac{1}{99}\) . 37 = \(\dfrac{37}{99}\)

0, (62) = 0, (01) . 62 = \(\dfrac{1}{99}\) . 62 = \(\dfrac{62}{99}\)

\(\Rightarrow\)0, (37) + 0, (62) = \(\dfrac{37}{99}\) + \(\dfrac{62}{99}\) = \(\dfrac{99}{99}\)= 1

Vậy 0, (37) + 0, (62) = 1 (ĐPCM)

b) Ta có:

0, (33) = 0, (01) . 33 = \(\dfrac{1}{99}\) . 33 = \(\dfrac{33}{99}\)

\(\Rightarrow\)0, (33) . 3 = \(\dfrac{33}{99}\) . 3 =\(\dfrac{99}{99}\) = 1

Vậy 0, (33) . 3 = 1 (ĐPCM)

tick mk nhé