Ta có: \(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{63}>\dfrac{1}{32}+\dfrac{1}{32}+..+\dfrac{1}{32}\left(có\right)62sốhạng\)
\(\Rightarrow\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{63}>\dfrac{1}{32}.63=\dfrac{63}{32}=2\)
\(\Rightarrow\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{63}>2\)(đây là điều cần chứng tỏ)
\(B=1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+.......+\dfrac{1}{63}\)Chứng tỏ rằng \(\dfrac{B}{3}\)không phải là 1 số nguyên
Chứng tỏ rằng: 1/2^2+1/3^2+1/4^2+.....+1/100^2<3/4
Chứng tỏ rằng:
\(\dfrac{1}{5}+\dfrac{1}{13}+\dfrac{1}{14}+\dfrac{1}{15}+\dfrac{1}{61}+\dfrac{1}{62}+\dfrac{1}{63}< \dfrac{1}{2}\)
Chứng tỏ rằng 1+1/2+1/3+1/4+..........+1/255+1/256>5
Chứng tỏ rằng 1+1/2+1/3+1/4+..........+1/255+1/256>5
Hãy chứng tỏ rằng: \(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+\dfrac{1}{5^2}+...+\dfrac{1}{n^2}\)<1
chứng tỏ rằng:
\(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+.....+\frac{1}{99^2}+\frac{1}{100^2}< \frac{3}{4}\)
giúp mình nhé mình đang cần gấp!
Chứng minh rằng : 1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{4}\) + ... + \(\dfrac{1}{63}\) < 6
A=\(\dfrac{1}{2^2}\)+ \(\dfrac{1}{3^2}\)+ \(\dfrac{1}{4^2}\)+ .....+\(\dfrac{1}{2008^2}\). Chứng tỏ rằng: A<1
