ta có: R1/R2=\(\frac{p1\cdot l1}{S1}\cdot\frac{S2}{p2\cdot l2}=\frac{S2}{S1}\)(do cùng chất, cùng chiều dài nên p1=p2;l1=l2)
Ta có : R1=ρ1\(\frac{l_1}{S_1}\)
R2=ρ2\(\frac{l_2}{S_2}\)
\(\frac{R_1}{R_2}\)=\(\frac{P1.l1}{S1}\).\(\frac{S2}{P2.l2}\)=\(\frac{S2}{S1}\)(ρ1=ρ2;l1=l2)
Vậy \(\frac{R_1}{R_2}\)=\(\frac{S_2}{S_1}\)
Giả sử dây dẫn có cùng p, cùng l
Ta có: \(R1=p\frac{l}{s1}\left(1\right)\)
\(R2=p\frac{l}{s2}\left(2\right)\)
\(\frac{\left(1\right)}{\left(2\right)}\Leftrightarrow\frac{R1}{R2}=\frac{p.l}{s1}.\frac{s2}{p.l}\)
\(\Rightarrow\frac{R1}{R2}=\frac{s2}{s1}\) (đpcm)