Question

Chứng minh

a, A = 1 + \(\dfrac{1}{4}\) + \(\dfrac{1}{16}\) + \(\dfrac{1}{36}\) + \(\dfrac{1}{64}\) + \(\dfrac{1}{100}\) + \(\dfrac{1}{144}\) + \(\dfrac{1}{196}\) < 1

b, B = 1 + \(\dfrac{1}{4}\) + \(\dfrac{1}{9}\) + \(\dfrac{1}{16}\) + .... + \(\dfrac{1}{81}\) + \(\dfrac{1}{100}\) > \(1\dfrac{65}{132}\)

Answer 1

Cho A = 1/2 .3/4.5/6.....199/200.Chứng tỏ rằng B mũ 2 <1/201.Bạn có làm dược ko ?