Ta có: \(3^{2016}=3^{504.4}=\overline{.....1}\)
Và: \(2^{2017}=2^{2016}.2=2^{2.1008}.2\)
Vì: \(2^{2.1008}=\overline{......6}\)
\(\Rightarrow2^{2017}=\overline{.....6}.2=\overline{.........2}\)
Vậy: \(3^{2016}.2^{2017}=\overline{.....1}.\overline{......2}=\overline{....2}\)