nH2=8,96/22,4=0,4(mol)
2Al+3H2SO4--->Al2(SO4)3+3H2
x_______3/2x_____________3/2x
Fe+H2SO4--->FeSO4+H2
y___y_______________y
Hệ pt:
\(\left\{{}\begin{matrix}27x+56y=11\\1,5x+y=0,4\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,2\\y=0,1\end{matrix}\right.\)
=>mAl=0,2.27=5,4(g)
=>%mAl=5,4/11.100%~49%
=>%mFe=100%-49%=51%
\(\Sigma nH2SO4\)=3/2x+y=0,4(mol)
=>mH2SO4=0,4.98=39,2(g)