\(P=\left(1+\dfrac{x}{y}\right)\left(1+\dfrac{y}{z}\right)\left(1+\dfrac{x}{z}\right)\\ =\dfrac{x+y}{y}.\dfrac{y+z}{z}.\dfrac{x+z}{z}\\ =\dfrac{-z}{y}.\dfrac{-x}{z}.\dfrac{-y}{x}\\ =\dfrac{-xyz}{xyz}=-1\)
Cho biểu thức hai biến: \(f\left(x,y\right)=\left(2x-3y+7\right)\left(3x+2y-1\right)\)
a, Tìm các giá trị của y sao cho phương trình ( ẩn x) f(x,y)=0 nhận x=-3 làm nghiệm
b, Tìm các giá trị của x sao cho phương trình ( ẩn y) f(x,y)=0 nhận y=2 làm nghiệm
a) \(\left(x^2-16\right)\left(\dfrac{x}{4}-\dfrac{4x+5}{3}\right)=0\)
b) \(\left(4x-1\right)\left(x+5\right)=x^2-25\)
c) \(x\left(x+3\right)^3-\dfrac{x}{4}\left(x+3\right)=0\)
a/8(3x-2) - 13x =5(12 - 3x) +7x
b/\(\dfrac{5x}{x+2}-\dfrac{3}{x-2}+\dfrac{3x^2+6}{\left(x-2\right)\left(x+2\right)}=0\)
c/\(\dfrac{x}{2\left(x-3\right)}+\dfrac{x}{2x+2}=\dfrac{2x}{\left(x+1\right)\left(x-3\right)}\)
a,\(\left(x+1\right)^2\left(x+2\right)+\left(x+1\right)^2\left(x-2\right)=-24\)
b, \(2x^3+3x^2+6x+5=0\)
c, \(\dfrac{3x-1}{x-1}+\dfrac{2x+5}{x+3}+\dfrac{4}{x^2+2x-3}=1\)
d, \(\dfrac{12x+1}{6x-2}-\dfrac{9x-5}{3x+1}=\dfrac{108x-36x^2-9}{4\left(9x^2-1\right)}\)
Giải các phương trình
a)3x-2=2x-3 c)11x+42-2x=100-9x-22
b)2x+3=5x+9 d)2x-(3-5x)=4(x+3)
e)\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)
f)\(\dfrac{x+4}{5}-x+4=\dfrac{x}{3}-\dfrac{x-2}{2}\)
g)(2x+1)(x-1)=0
h)(x+\(\dfrac{2}{3}\))(x-\(\dfrac{1}{2}\))=0
i)(3x-1)(2x-3)(2x-3)(x+5)=0
k)3x-15=2x(x-5)
m)\(\left|x-2\right|=3\)
n)\(\left|x+1\right|=\left|2x+3\right|\)
j)\(\dfrac{7x-3}{x-1}=\dfrac{2}{3}\)
đ)\(\dfrac{2\left(3-7x\right)}{1+x}=\dfrac{1}{2}\)
y)\(\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}=\dfrac{20}{x^2-25}\)
\(\dfrac{1}{x-1}+\dfrac{2}{x+1}=\dfrac{x}{x^2-1}\)
a/(x-2)(x2-1)=0
b/\(\dfrac{-1}{1-x}-\dfrac{7}{x+2}=\dfrac{3}{\left(x-1\right)\left(x+2\right)}\)
c/10x-2(2x+4)=2x
Giải phương trình : \(\left(\dfrac{x+2}{98}+1\right)+\left(\dfrac{x+3}{97}+1\right)=\left(\dfrac{x+4}{96}+1\right)+\left(\dfrac{x+5}{95}+1\right)\)
giải phương trình
1)\(2\left(x-3\right)+1=2\left(x+1\right)-9\)
2)\(\dfrac{5-x}{2}=\dfrac{3x-4}{6}\)
3) \(\left(x-1\right)^2+\left(x+2\right)\left(x-2\right)=\left(2x+1\right)\left(x-3\right)\)
4)\(\left(x+5\right)\left(x-1\right)-\left(x+1\right)\left(x+2\right)=1\)
5) \(\dfrac{6x-1}{15}-\dfrac{x}{5}=\dfrac{2x}{3}\)
6)\(\dfrac{5\left(x-2\right)}{2}-\dfrac{x+5}{3}=1-\dfrac{4\left(x-3\right)}{5}\)
bài 1:chứng tỏ rằng pt có vô số nghiệm
a)\(\left(x+2\right)^2=x^2+4x+4\)
b)\(\left(3-x\right)^2=x^2-6x+9\)
bài 2:xét xem pt có tương đương k?
a)\(x+2=0\) và \(\dfrac{x}{x+2}=0\)
b)\(x^2+\dfrac{1}{x}=x+\dfrac{1}{x}\) và \(x^2+x=0\)
c)\(\left|x-1\right|=2\) và \(\left(x+1\right)\left(x-3\right)=0\)
d)\(x+5=0\) và \(\left(x+5\right)\left(x^2+1\right)=0\)
