Question

cho tam giác ABC , bên ngoài vẽ các hbh ABIF,BCPQ,CARS. Chứng minh : \(\overrightarrow{RF}+\overrightarrow{IQ}+\overrightarrow{PS}=\overrightarrow{0}\)

Answer 1

\(\overrightarrow{RF}+\overrightarrow{IQ}+\overrightarrow{PS}=\overrightarrow{RA}+\overrightarrow{AF}+\overrightarrow{IB}+\overrightarrow{BQ}+\overrightarrow{PC}+\overrightarrow{CS}=\overrightarrow{0}\)

Answer 2

ta có : \(\overrightarrow{RF}+\overrightarrow{IQ}+\overrightarrow{PS}\)

\(=\overrightarrow{RA}+\overrightarrow{AB}+\overrightarrow{BF}+\overrightarrow{IB}+\overrightarrow{BC}+\overrightarrow{CQ}+\overrightarrow{PC}+\overrightarrow{CA}+\overrightarrow{AS}\)

\(=\overrightarrow{RA}+\overrightarrow{BF}+\overrightarrow{IB}+\overrightarrow{CQ}+\overrightarrow{PC}+\overrightarrow{AS}\) \(=\overrightarrow{RS}+\overrightarrow{IF}+\overrightarrow{PQ}=\overrightarrow{AC}+\overrightarrow{BA}+\overrightarrow{CB}=\overrightarrow{0}\left(đpcm\right)\)

Answer 3

Akai Haruma