\(P^2=\left(1.x-\sqrt{5}.y\right)^2\le\left(1+5\right)\left(x^2+y^2\right)=36\)
\(\Rightarrow-6\le P\le6\)
\(P_{min}=-6\) khi \(\left\{{}\begin{matrix}x=-1\\y=\sqrt{5}\end{matrix}\right.\)
\(P_{max}=6\) khi \(\left\{{}\begin{matrix}x=1\\y=-\sqrt{5}\end{matrix}\right.\)