Question

Cho R1= 3Ω, R2= 6Ω, R3= 8Ω, I5 R4= 10Ω, R5= 5Ω.

Uab= 100V

Tính Rtđ và I1, I2, I3, I4, I5

Answer 1

https://i.imgur.com/oYzoCR6.jpg

Answer 2

R₁₂= \(\frac{R1.R2}{R1+R2}=\frac{3.6}{3+6}=2\left(\Omega\right)\)

R123=R12+R3=2+8=10(Ω)

R1234=\(\frac{R123.R4}{R123+R4}=\frac{10.10}{10+10}=5\left(\Omega\right)\)

R_tđ=R1234+R5=5+5=10(Ω)

I_mạch=\(\frac{U_{ab}}{R_{tđ}}=\frac{100}{10}=10\left(A\right)=I_5\)

I₄=\(\frac{R123}{R123+R4}.I_{mạch}=\frac{10}{10+10}.10=5\left(A\right)\)

I₁₂₃=I_mạch-I₄=10-5=5(A)=I₃

I₁=\(\frac{R2}{R1+R2}.I_{123}=\frac{6}{3+6}.5=\frac{10}{3}\left(A\right)\)

I₂=I₁₂₃-I₁=5-\(\frac{10}{3}\)= \(\frac{5}{3}\left(A\right)\)