Theo đl Viet: \(\left\{{}\begin{matrix}x_1+x_2=4\\x_1x_2=-3\end{matrix}\right.\)
\(\left(x_1-x_2\right)^2=\left(x_1+x_2\right)^2-4x_1x_2=16-\left(-3\right).4=28\)
\(\Rightarrow x_1-x_2=\pm\sqrt{28}=\pm2\sqrt{7}\)
\(\Rightarrow A=\left(x_1-x_2\right)\left(x_1+x_2\right)=\pm2\sqrt{7}.4=\pm8\sqrt{7}\)