\(Zn+X_2\rightarrow ZnX_2\)
\(2K+X_2\rightarrow2KX\)
\(n_{X2}=n_{ZnX2}=\frac{13,6}{65+2M_X}\)
\(n_{Kk}=\frac{14,9}{39+M_X}\)
\(\Rightarrow n_{X2}=\frac{14,9}{39+M_X}:2=\frac{7,45}{39+M_X}\)
Ta có
\(\frac{13,6}{65+2M_X}=\frac{7,45}{39+M_X}\)
\(\Leftrightarrow M_X=35,5\)
Vậy X là Clo