\(R+nHCl\rightarrow RCln+\frac{n}{2}H_2\)
\(R+nH_2O\rightarrow R\left(OH\right)_n+\frac{n}{2}H_2\)
\(\rightarrow n_{HCl}+n_{H2O}=2nH_2=0,045a\left(mol\right)\)
Giả sử a=100 \(\rightarrow\) mHCl=x gam \(\rightarrow\) mH2O=100-x gam
\(\rightarrow n_{HCl}+n_{H2O}=4,5=\frac{x}{36,5}+\frac{100-x}{18}\rightarrow x=37,5\)