Ta có:(\(\sqrt{x^2+\sqrt{2017}}\)+x)(\(\sqrt{x^2+\sqrt{2017}}\)-x)=\(\sqrt{2017}\)
Từ bài sa suy ra:\(\sqrt{x^2+\sqrt{2017}}-x\)=\(\sqrt{y^2+\sqrt{2017}}\)+y
suy ra: x+y=\(\sqrt{x^2+\sqrt{2017}}-\sqrt{y^2+\sqrt{2017}}\) (1)
CMTT ta có:\(\sqrt{y^2+\sqrt{2017}}-y=\sqrt{x^2+\sqrt{2017}}+x\)
suy ra: x+y=\(\sqrt{y^2+\sqrt{2017}}-\sqrt{x^2+\sqrt{2017}}\) (2)
Từ (1),(2) suy ra x+y=0